What is the inverse of f(x)=2x^2-1 ?

The inverse of f(x)=2x^2-1 is sqrt((x+1)/2),-sqrt((x+1)/2)

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inverse of f(x)=2x^2-1

inverse

f (x) = 2 x^{2} - 1

\frac{x + 1}{2}, - \frac{x + 1}{2}

Solution steps

y = 2 x^{2} - 1

Replace

x

with

y

x = 2 y^{2} - 1

Solve for

y, x = 2 y^{2} - 1

\frac{x + 1}{2}, - \frac{x + 1}{2}

f (x) = 4 x^{4} + 16 x^{3}

f (x) = \frac{35}{x ^{2} + 7 x}

0.0417 D (a + 1)

f (x) = 25 - x

f (x) = \frac{x ( x - 2 ) ^{2}}{( x + 5 ) ^{3}}

What is the inverse of f(x)=2x^2-1 ?
The inverse of f(x)=2x^2-1 is sqrt((x+1)/2),-sqrt((x+1)/2)