What is the range of y=-3sin(x) ?

The range of y=-3sin(x) is -3<= f(x)<= 3

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range of y=-3sin(x)

range

y = - 3 sin (x)

- 3 \leq f (x) \leq 3

Interval Notation

[- 3, 3]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (x) \leq 1

- 1 \leq sin (x) \leq 1

Multiply the edges of the range by:

- 3

- 3 \leq - 3 sin (x) \leq 3

Therefore the range is

- 3 \leq f (x) \leq 3

(- 7, 0), (0, - 2)

- 8 x^{4} + 5 x^{2} - x + 7

f (x) = \frac{2 x - 4}{3}

\frac{3}{x + 5}

y = 8 x + 3