What is the domain of f(x)= 1/x-7/(x+2) ?

The domain of f(x)= 1/x-7/(x+2) is x 0

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domain of f(x)= 1/x-7/(x+2)

domain

f (x) = \frac{1}{x} - \frac{7}{x + 2}

x < - 2 or - 2 < x < 0 or x > 0

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2

The function domain

x < - 2 or - 2 < x < 0 or x > 0

\frac{x + 1}{2 x - 4}

f (x) = \frac{1}{2} x - 1

f (x) = \frac{x ^{2} - 9}{ln ( x + 1 )}

f (x) = 2^{x} - 7

\frac{4 x ^{2} - 16 x + 17}{x ^{2} - 4 x + 4}

What is the domain of f(x)= 1/x-7/(x+2) ?
The domain of f(x)= 1/x-7/(x+2) is x<-2\lor-2<x<0\lor x>0