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Popular >

midpoint (3,-6),(7,10)

Solution

midpoint

(3, - 6), (7, 10)

Solution

(5, 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, - 6), (x_{2}, y_{2}) = (7, 10)

= (\frac{7 + 3}{2}, \frac{10 - 6}{2})

Refine

= (5, 2)

Popular Examples

critical \sqrt[5]{x}(x-2)critical points

inverse of f(x)=(7-x)^{1/4}inverse

f (x) = (7 - x)^{\frac{1}{4}}

range of 2x^2-x+4 range

2 x^{2} - x + 4

domain of sqrt(x)+sqrt(7-x)domain

x + 7 - x

inverse of f(x)=(x^5)/6+7 inverse

f (x) = \frac{x ^{5}}{6} + 7

Frequently Asked Questions (FAQ)

What is the midpoint (3,-6),(7,10) ?
The midpoint (3,-6),(7,10) is (5,2)