What is the domain of f(x)= 1/(\sqrt[4]{x^2-8x)} ?

The domain of f(x)= 1/(\sqrt[4]{x^2-8x)} is x 8

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domain of f(x)= 1/(\sqrt[4]{x^2-8x)}

domain

x < 0 or x > 8

Interval Notation

(- \infty, 0) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 8

Find undefined (singularity) points:

x = 8, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 8

f (x) = \frac{x + 1}{x ^{2} + 4}

f (x) = x^{(\frac{1}{x})}

f (x) = e^{- x}

f (x) = \frac{x}{x ^{2} - 4 x + 3}

h (x) = \frac{4 x}{7 x - 3}

What is the domain of f(x)= 1/(\sqrt[4]{x^2-8x)} ?
The domain of f(x)= 1/(\sqrt[4]{x^2-8x)} is x<0\lor x>8