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Popular >

midpoint (1,-7),(1,-12)

Solution

midpoint

(1, - 7), (1, - 12)

Solution

(1, - \frac{19}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (1, - 7), (x_{2}, y_{2}) = (1, - 12)

= (\frac{1 + 1}{2}, \frac{- 12 - 7}{2})

Refine

= (1, - \frac{19}{2})

Popular Examples

inverse of f(x)=x^2-14 inverse

f (x) = x^{2} - 14

extreme f(x)=7x^2ln(x/4)extreme points

f (x) = 7 x^{2} ln (\frac{x}{4})

range of f(x)=x^2-6x range

f (x) = x^{2} - 6 x

range of f(x)=-5x^2+2x+8 range

f (x) = - 5 x^{2} + 2 x + 8

domain of sqrt(4-6a)domain

4 - 6 a

Frequently Asked Questions (FAQ)

What is the midpoint (1,-7),(1,-12) ?
The midpoint (1,-7),(1,-12) is (1,-19/2)