What is the domain of f(x)=(9x-6)/(sqrt(x+9)) ?

The domain of f(x)=(9x-6)/(sqrt(x+9)) is x>-9

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domain of f(x)=(9x-6)/(sqrt(x+9))

domain

f (x) = \frac{9 x - 6}{x + 9}

x > - 9

Interval Notation

(- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = - 9

Combine real regions and undefined points for final function domain

x > - 9

f (x) = x^{7}

x + 4 + 7

\frac{- 2 x + 4}{x ^{2} - 4}

What is the domain of f(x)=(9x-6)/(sqrt(x+9)) ?
The domain of f(x)=(9x-6)/(sqrt(x+9)) is x>-9