What is the inverse of f(x)=((x+1))/(x-4) ?

The inverse of f(x)=((x+1))/(x-4) is (1+4x)/(x-1)

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inverse of f(x)=((x+1))/(x-4)

inverse

f (x) = \frac{( x + 1 )}{x - 4}

\frac{1 + 4 x}{x - 1}

Solution steps

y = \frac{x + 1}{x - 4}

Replace

x

with

y

x = \frac{y + 1}{y - 4}

Solve for

y, x = \frac{y + 1}{y - 4}

\frac{1 + 4 x}{x - 1}

f (x) = 3 x^{2} + 4 x + 1

y = 3 cot (\frac{1}{2} x) - 2

y + 3 = \frac{3}{4} + 5

f (x) = 4 x - 4

y = \frac{3}{7} x - 3

What is the inverse of f(x)=((x+1))/(x-4) ?
The inverse of f(x)=((x+1))/(x-4) is (1+4x)/(x-1)