What is the domain of f(x)= 1/(arccos(t-2)) ?

The domain of f(x)= 1/(arccos(t-2)) is 1<= t<3

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domain of f(x)= 1/(arccos(t-2))

domain

f (x) = \frac{1}{arccos ( t - 2 )}

1 \leq t < 3

Interval Notation

[1, 3)

Solution steps

Find known functions domain restrictions:

1 \leq t \leq 3

Find undefined (singularity) points:

t = 3

Combine real regions and undefined points for final function domain

1 \leq t < 3

y = 9 x^{2}

f (x) = lo g_{5} (x + 2)

f (x) = \frac{5 x + 2}{x - 3}

y = - 10 x + 14

y = - 13 x

What is the domain of f(x)= 1/(arccos(t-2)) ?
The domain of f(x)= 1/(arccos(t-2)) is 1<= t<3