What is the inverse of f(x)=(x-3)^2+7 ?

The inverse of f(x)=(x-3)^2+7 is sqrt(x-7)+3,-sqrt(x-7)+3

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inverse of f(x)=(x-3)^2+7

inverse

f (x) = (x - 3)^{2} + 7

x - 7 + 3, - x - 7 + 3

Solution steps

y = (x - 3)^{2} + 7

Replace

x

with

y

x = (y - 3)^{2} + 7

Solve for

y, x = (y - 3)^{2} + 7

x - 7 + 3, - x - 7 + 3

f (x) = \frac{\frac{- x + 1}{x} + 2}{\frac{- x + 1}{x} - 9}

f (t) = t^{2}

f (x) = (x + 7)^{3} - 2

f (x) = 2 x - 3

\frac{( 8 - 3 x + x ^{2} )}{( ( x - 2 ) ( 8 - x ) )}

What is the inverse of f(x)=(x-3)^2+7 ?
The inverse of f(x)=(x-3)^2+7 is sqrt(x-7)+3,-sqrt(x-7)+3