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Popular >

range of x^2+2

Solution

range

x^{2} + 2

Solution

f (x) \geq 2

+1

Interval Notation

[2, \infty)

Solution steps

Vertex of

x^{2} + 2 :

Minimum

(0, 2)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (0, 2)

f (x) \geq 2

Popular Examples

domain of x^2-x+1 domain

x^{2} - x + 1

inverse of f(x)=-2/(x-2)+1 inverse

f (x) = - \frac{2}{x - 2} + 1

simplify (4.1)(-1.6)simplify

(4.1) (- 1.6)

inverse of f(x)= 8/(x^2+1)inverse

f (x) = \frac{8}{x ^{2} + 1}

intercepts of f(x)=2x^2+4x-3 intercepts

f (x) = 2 x^{2} + 4 x - 3

Frequently Asked Questions (FAQ)

What is the range of x^2+2 ?
The range of x^2+2 is f(x)>= 2