What is the domain of f(x)=sqrt(t+6) ?

The domain of f(x)=sqrt(t+6) is t>=-6

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domain of f(x)=sqrt(t+6)

domain

f (x) = t + 6

t \geq - 6

Interval Notation

[- 6, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 6

The function domain

t \geq - 6

- \frac{36 ( x - 1 )}{( x + 3 ) ^{3}}

f (x) = 7 x - 6

(1) (0.2)

f (x) = (x - 6)^{\frac{2}{3}}

f (x) = 15 cos (\frac{1}{2}) (x + \frac{π}{2})