What is the inverse of f(x)=(x+1)/(2x-3) ?

The inverse of f(x)=(x+1)/(2x-3) is (1+3x)/(2x-1)

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inverse of f(x)=(x+1)/(2x-3)

inverse

f (x) = \frac{x + 1}{2 x - 3}

\frac{1 + 3 x}{2 x - 1}

Solution steps

y = \frac{x + 1}{2 x - 3}

Replace

x

with

y

x = \frac{y + 1}{2 y - 3}

Solve for

y, x = \frac{y + 1}{2 y - 3}

\frac{1 + 3 x}{2 x - 1}

f (x) = 2 x^{3} + 2 x^{2} - 3

f (x) = x^{4} - 4

n g l e (1.0594 + 0.1517 i)

cos (2 π t)

f (x) = - 0.75 x

What is the inverse of f(x)=(x+1)/(2x-3) ?
The inverse of f(x)=(x+1)/(2x-3) is (1+3x)/(2x-1)