What is the inverse of f(x)=(8x-10)/(-8x-1) ?

The inverse of f(x)=(8x-10)/(-8x-1) is -(-10+x)/(8(1+x))

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inverse of f(x)=(8x-10)/(-8x-1)

inverse

f (x) = \frac{8 x - 10}{- 8 x - 1}

- \frac{- 10 + x}{8 ( 1 + x )}

Solution steps

y = \frac{8 x - 10}{- 8 x - 1}

Replace

x

with

y

x = \frac{8 y - 10}{- 8 y - 1}

Solve for

y, x = \frac{8 y - 10}{- 8 y - 1}

- \frac{- 10 + x}{8 ( 1 + x )}

f (x) = \frac{x ^{2} + 1}{7 x - 2 x ^{2}}

7 x + 5 y = 10

y = 27 - x^{3}

x^{3} - 1

f (x) = x^{2} + 4 x - 5

What is the inverse of f(x)=(8x-10)/(-8x-1) ?
The inverse of f(x)=(8x-10)/(-8x-1) is -(-10+x)/(8(1+x))