What is the domain of f(x)= 1/(x^2+2) ?

The domain of f(x)= 1/(x^2+2) is -infinity <x<infinity

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domain of f(x)= 1/(x^2+2)

domain

f (x) = \frac{1}{x ^{2} + 2}

- \infty < x < \infty

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - 2 (x - 2)^{2} + 7

\frac{3 x + 4}{10 x - 12}

- x^{4} + 4 x^{3} - 4 x + 19

\frac{3 x}{x + 6}

f (x) = \frac{2}{x ^{2} - 16}

What is the domain of f(x)= 1/(x^2+2) ?
The domain of f(x)= 1/(x^2+2) is -infinity <x<infinity