en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

distance (7,8),(2,2)

Solution

distance

(7, 8), (2, 2)

Solution

61

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(7, 8)

and

(2, 2)

is

= (2 - 7)^{2} + (2 - 8)^{2}

Simplify

= 61

Graph

Popular Examples

parity f(x)=((3x^3+2x+2))/((4x^3+5x-5))parity

f (x) = \frac{( 3 x ^{3} + 2 x + 2 )}{( 4 x ^{3} + 5 x - 5 )}

simplify (20.1)(19.14)simplify

(20.1) (19.14)

distance (-4,-4),(-7,2)distance

(- 4, - 4), (- 7, 2)

inverse of f(x)=\sqrt[5]{2x-1}-1 inverse

f (x) = 5 2 x - 1 - 1

critical (x^2-4)/(x-2)critical points

\frac{x ^{2} - 4}{x - 2}

Frequently Asked Questions (FAQ)

What is the distance (7,8),(2,2) ?
The distance (7,8),(2,2) is square root of 61