What is the domain of f(x)=sqrt(x+12)+3 ?

The domain of f(x)=sqrt(x+12)+3 is x>=-12

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domain of f(x)=sqrt(x+12)+3

domain

f (x) = x + 12 + 3

x \geq - 12

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 12

The function domain

x \geq - 12

f (x) = 25 - x^{2}

y = 2 x + 10

f (x) = \frac{e ^{x}}{1 + 9 e ^{x}}

y = 2 x - 1

\frac{( 2 ln ( x ) - 1 )}{ln ( x ) + 2}

What is the domain of f(x)=sqrt(x+12)+3 ?
The domain of f(x)=sqrt(x+12)+3 is x>=-12