What is the inverse of f(x)=2x^2+5 ?

The inverse of f(x)=2x^2+5 is sqrt((x-5)/2),-sqrt((x-5)/2)

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inverse of f(x)=2x^2+5

inverse

f (x) = 2 x^{2} + 5

\frac{x - 5}{2}, - \frac{x - 5}{2}

Solution steps

y = 2 x^{2} + 5

Replace

x

with

y

x = 2 y^{2} + 5

Solve for

y, x = 2 y^{2} + 5

\frac{x - 5}{2}, - \frac{x - 5}{2}

f (x) = x + 1 - \frac{1}{x}

f (x) = \frac{2}{x} - 1

f (x) = - 9 + 8 x - x^{3}

2 x^{2} - 7 x

x^{3} - 3

What is the inverse of f(x)=2x^2+5 ?
The inverse of f(x)=2x^2+5 is sqrt((x-5)/2),-sqrt((x-5)/2)