What is the domain of f(x)=sqrt(3-x)-sqrt(2+x) ?

The domain of f(x)=sqrt(3-x)-sqrt(2+x) is -2<= x<= 3

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domain of f(x)=sqrt(3-x)-sqrt(2+x)

domain

f (x) = 3 - x - 2 + x

- 2 \leq x \leq 3

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 3

The function domain

- 2 \leq x \leq 3

y = - 3 x + 9

2 x - y = 4

f (x) = x^{3} + 6 x^{2} - 15 x

f (x) = \frac{2}{x - 6}

f (x) = 4 x^{3} - 54 x^{2} + 180

What is the domain of f(x)=sqrt(3-x)-sqrt(2+x) ?
The domain of f(x)=sqrt(3-x)-sqrt(2+x) is -2<= x<= 3