What is the inverse of f(x)= 1/4 x^2-5 ?

The inverse of f(x)= 1/4 x^2-5 is 2sqrt(x+5),-2sqrt(x+5)

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inverse of f(x)= 1/4 x^2-5

inverse

f (x) = \frac{1}{4} x^{2} - 5

2 x + 5, - 2 x + 5

Solution steps

y = \frac{1}{4} x^{2} - 5

Replace

x

with

y

x = \frac{1}{4} y^{2} - 5

Solve for

y, x = \frac{1}{4} y^{2} - 5

2 x + 5, - 2 x + 5

8

\frac{x ^{2}}{x ^{2} + 4}

f (x) = \frac{x + 17}{x - 16}

h (x) = (x + 1)^{3} + 3

f (x) = 2 ∣ x ∣ - 3

What is the inverse of f(x)= 1/4 x^2-5 ?
The inverse of f(x)= 1/4 x^2-5 is 2sqrt(x+5),-2sqrt(x+5)