What is the inverse of f(x)=((x-3))/(x+8) ?

The inverse of f(x)=((x-3))/(x+8) is (-3-8x)/(x-1)

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inverse of f(x)=((x-3))/(x+8)

inverse

f (x) = \frac{( x - 3 )}{x + 8}

\frac{- 3 - 8 x}{x - 1}

Solution steps

y = \frac{x - 3}{x + 8}

Replace

x

with

y

x = \frac{y - 3}{y + 8}

Solve for

y, x = \frac{y - 3}{y + 8}

\frac{- 3 - 8 x}{x - 1}

3 x - 5 y + 12 = 0

- 3 + 2 sin (x + \frac{π}{6})

f (x) = x^{4} - 4 x^{2}

9 x + 3 y = - 6

ln (arctan (7 x^{4}))

What is the inverse of f(x)=((x-3))/(x+8) ?
The inverse of f(x)=((x-3))/(x+8) is (-3-8x)/(x-1)