What is the inverse of f(x)= 1/2 x^2 ?

The inverse of f(x)= 1/2 x^2 is sqrt(2)sqrt(x),-sqrt(2)sqrt(x)

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inverse of f(x)= 1/2 x^2

inverse

f (x) = \frac{1}{2} x^{2}

2 x, - 2 x

Solution steps

y = \frac{1}{2} x^{2}

Replace

x

with

y

x = \frac{1}{2} y^{2}

Solve for

y, x = \frac{1}{2} y^{2}

2 x, - 2 x

3 + cos (2 t)

f (x) = \frac{x - 7}{x ^{2} - 49}

x^{2} + 2 x + 12

16 - x^{2}

f (x) = \frac{x - 2}{x ^{2} - 4} + \frac{1}{x}

What is the inverse of f(x)= 1/2 x^2 ?
The inverse of f(x)= 1/2 x^2 is sqrt(2)sqrt(x),-sqrt(2)sqrt(x)