What is the critical 1/(x^2-2x+9) ?

The critical 1/(x^2-2x+9) is x=1

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critical 1/(x^2-2x+9)

critical points

\frac{1}{x ^{2} - 2 x + 9}

x = 1

Solution steps

\frac{1}{x ^{2} - 2 x + 9}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{x ^{2} - 2 x + 9} : - \infty < x < \infty

All critical points are in domain

x = 1

\frac{x - 5}{3}

y = \frac{x}{x ^{2} - 4}

y = \frac{3}{2} x + 5

- 2 (e^{x}) - 1

f (x) = x^{3} - 3 x^{2} - 9 x + 3