What is the vertices y=x^2-2x-24 ?

The vertices y=x^2-2x-24 is Minimum (1,-25)

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vertices y=x^2-2x-24

vertices

y = x^{2} - 2 x - 24

Minimum (1, - 25)

Solution steps

y = x^{2} - 2 x - 24

The parabola parameters are:

a = 1, b = - 2, c = - 24

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 2 )}{2 \cdot 1}

Simplify

x_{v} = 1

Plug in

x_{v} = 1

to find the

y_{v}

value

y_{v} = - 25

Therefore the parabola vertex is

(1, - 25)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (1, - 25)

f (x) = x^{2} - 6 x + 8

f (x) = (\frac{x}{1 + x ^{2}})

f (x) = ln (7 - x)

\frac{3}{x + 5}