What is the inverse of f(x)=(-7x+9)/(-4x-3) ?

The inverse of f(x)=(-7x+9)/(-4x-3) is (9+3x)/(-4x+7)

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inverse of f(x)=(-7x+9)/(-4x-3)

inverse

f (x) = \frac{- 7 x + 9}{- 4 x - 3}

\frac{9 + 3 x}{- 4 x + 7}

Solution steps

y = \frac{- 7 x + 9}{- 4 x - 3}

Replace

x

with

y

x = \frac{- 7 y + 9}{- 4 y - 3}

Solve for

y, x = \frac{- 7 y + 9}{- 4 y - 3}

\frac{9 + 3 x}{- 4 x + 7}

f (x) = \frac{x ^{2} - 9}{x - 5}

y + 3 = \frac{1}{2} (x + 10)

lo g_{\frac{1}{3}} (x)

f (3) = \frac{9}{3 - 10 x} - 3

f (x) = 9 cos (\frac{1}{4} π x - π) - 2

What is the inverse of f(x)=(-7x+9)/(-4x-3) ?
The inverse of f(x)=(-7x+9)/(-4x-3) is (9+3x)/(-4x+7)