What is the amplitude of-2sin(3x+pi/2) ?

The amplitude of-2sin(3x+pi/2) is 2

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amplitude of-2sin(3x+pi/2)

amplitude

- 2 sin (3 x + \frac{π}{2})

2

Solution steps

f (x) = - 2 sin (3 x + \frac{π}{2}), A = - 2

Therefore, the amplitude |A| is

2

2

(2.25, 2.25), (- 1.5, 5.79)

f (x) = \frac{7}{x ^{2} - 16}

y = \frac{x + 4}{x - 5}

f (x) = \frac{3 + 4 x}{1 - 5 x}

f (x) = \frac{( 4 x ^{2} - x )}{( x ^{2} - 1 )}