What is the asymptotes of f(x)=(2(x+2))/(5x+7) ?

The asymptotes of f(x)=(2(x+2))/(5x+7) is Vertical: x=-7/5 ,Horizontal: y= 2/5

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asymptotes of f(x)=(2(x+2))/(5x+7)

asymptotes

f (x) = \frac{2 ( x + 2 )}{5 x + 7}

Vertical : x = - \frac{7}{5}, Horizontal : y = \frac{2}{5}

Solution steps

Vertical asymptotes of

\frac{2 ( x + 2 )}{5 x + 7} : x = - \frac{7}{5}

Horizontal Asymptotes of

\frac{2 ( x + 2 )}{5 x + 7} : y = \frac{2}{5}

Slant Asymptotes of

\frac{2 ( x + 2 )}{5 x + 7} :

None

Vertical : x = - \frac{7}{5}, Horizontal : y = \frac{2}{5}

y = - \frac{1}{4 x} x^{2} + 9 x - 8

f (x) = \frac{1}{2} x^{4} + 5 x^{3}

y = 4 x + 7

\frac{( 1 - 5 t )}{2 + t}

\frac{3 x}{x ^{2} - 1}

What is the asymptotes of f(x)=(2(x+2))/(5x+7) ?
The asymptotes of f(x)=(2(x+2))/(5x+7) is Vertical: x=-7/5 ,Horizontal: y= 2/5