What is the domain of f(x)=(sqrt(x+1))/(x-1) ?

The domain of f(x)=(sqrt(x+1))/(x-1) is -1 1

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domain of f(x)=(sqrt(x+1))/(x-1)

domain

f (x) = \frac{x + 1}{x - 1}

- 1 \leq x < 1 or x > 1

Interval Notation

[- 1, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

- 1 \leq x < 1 or x > 1

y = - 4 x + 5

(0, 4), (- 4, - 12)

f (x) = \frac{6 - 3 x}{x - 8}

f (x) = - x^{2} + 2 x - 4

\frac{x ^{2} - 6 x + 8}{x - 2}

What is the domain of f(x)=(sqrt(x+1))/(x-1) ?
The domain of f(x)=(sqrt(x+1))/(x-1) is -1<= x<1\lor x>1