What is the domain of f(x)=sqrt((x+3)(-x^2+25)) ?

The domain of f(x)=sqrt((x+3)(-x^2+25)) is x<=-5\lor-3<= x<= 5

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domain of f(x)=sqrt((x+3)(-x^2+25))

domain

f (x) = (x + 3) (- x^{2} + 25)

x \leq - 5 or - 3 \leq x \leq 5

Interval Notation

(- \infty, - 5] \cup [- 3, 5]

Solution steps

Find non-negative values for radicals:

x \leq - 5 or - 3 \leq x \leq 5

The function domain

x \leq - 5 or - 3 \leq x \leq 5

\frac{x + 3}{x - 1}

f (x) = \frac{8 x ^{2}}{x - 8}

(7, 0), (7, 8)

- y - x = - 5

4 x - 5 y = - 10 (6.3)

What is the domain of f(x)=sqrt((x+3)(-x^2+25)) ?
The domain of f(x)=sqrt((x+3)(-x^2+25)) is x<=-5\lor-3<= x<= 5