What is the domain of (sqrt(x+2))/(x-8) ?

The domain of (sqrt(x+2))/(x-8) is -2 8

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domain of (sqrt(x+2))/(x-8)

domain

\frac{x + 2}{x - 8}

- 2 \leq x < 8 or x > 8

Interval Notation

[- 2, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 2 \leq x < 8 or x > 8

f (x) = cot (2 x)

x + 1 - 3

f (x) = x - 8

\frac{x ^{3}}{x ^{2} - 4}

f (x) = 2^{x}

What is the domain of (sqrt(x+2))/(x-8) ?
The domain of (sqrt(x+2))/(x-8) is -2<= x<8\lor x>8