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Popular >

midpoint (-5,4),(3,-1)

Solution

midpoint

(- 5, 4), (3, - 1)

Solution

(- 1, \frac{3}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 5, 4), (x_{2}, y_{2}) = (3, - 1)

= (\frac{3 - 5}{2}, \frac{- 1 + 4}{2})

Refine

= (- 1, \frac{3}{2})

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f (x) = \frac{( 5 x )}{x + 7}

asymptotes of f(x)=(x^2-2x-1)/(1-x)asymptotes

f (x) = \frac{x ^{2} - 2 x - 1}{1 - x}

parity y=(1-e^x)^{1/(e^x)}parity

y = (1 - e^{x})^{\frac{1}{e ^{x}}}

domain of f(x)= 1/(x+8)domain

f (x) = \frac{1}{x + 8}

Frequently Asked Questions (FAQ)

What is the midpoint (-5,4),(3,-1) ?
The midpoint (-5,4),(3,-1) is (-1, 3/2)