What is the domain of f(x)=(sqrt(3-2x))-(sqrt(x+4)) ?

The domain of f(x)=(sqrt(3-2x))-(sqrt(x+4)) is -4<= x<= 3/2

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domain of f(x)=(sqrt(3-2x))-(sqrt(x+4))

domain

f (x) = (3 - 2 x) - (x + 4)

- 4 \leq x \leq \frac{3}{2}

Interval Notation

[- 4, \frac{3}{2}]

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq \frac{3}{2}

The function domain

- 4 \leq x \leq \frac{3}{2}

\frac{x + 1}{x + 3}

f (x) = \frac{2 x ^{2} + 1}{3 x - 5}

\frac{1}{x - 3}

f (x) = - 4 x + 4

f (x) = 4 x^{3} - 6 x^{2} + 8 x - 8

What is the domain of f(x)=(sqrt(3-2x))-(sqrt(x+4)) ?
The domain of f(x)=(sqrt(3-2x))-(sqrt(x+4)) is -4<= x<= 3/2