What is the inflection f(x)=4x^3-6x^2+8x-8 ?

The inflection f(x)=4x^3-6x^2+8x-8 is (1/2 ,-5)

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inflection f(x)=4x^3-6x^2+8x-8

inflection points

f (x) = 4 x^{3} - 6 x^{2} + 8 x - 8

(\frac{1}{2}, - 5)

Solution steps

f^{''} (x) = 24 x - 12

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

4 x^{3} - 6 x^{2} + 8 x - 8 : - 5

(\frac{1}{2}, - 5)

\frac{2 x - 3}{x ^{2} - 4}

9 - (2 y + 4 x) = 4 (x - y)

f (x) = \frac{- 1 + 4 x}{x - 3}

f (x) = \frac{2 - 7 ( - 2 )}{( - 2 ) - 1}

f (x) = \frac{x - 5}{3}

What is the inflection f(x)=4x^3-6x^2+8x-8 ?
The inflection f(x)=4x^3-6x^2+8x-8 is (1/2 ,-5)