What is the domain of y=tan(x) ?

The domain of y=tan(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin

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domain of y=tan(x)

domain

y = tan (x)

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Solution steps

Take the denominator(s) of

tan (x)

and compare to zero:

x = \frac{π}{2} + πn

Periodicity of

tan (x) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

x^{2} + 4

(0, - 1), (8, 7)

y = \frac{x - 1}{x ^{2} - 9}

ln (x + 6)

x + 3

What is the domain of y=tan(x) ?
The domain of y=tan(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin