What is the inflection f(x)= x/(x^3-1) ?

The inflection f(x)= x/(x^3-1) is (-\sqrt[3]{2},(\sqrt[3]{2})/3)

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inflection f(x)= x/(x^3-1)

inflection points

f (x) = \frac{x}{x ^{3} - 1}

Solution steps

f^{''} (x) = - \frac{6 x ^{2} ( - x ^{3} - 2 )}{( x ^{3} - 1 ) ^{3}}

Find intervals:

Concave Upward

Concave Downward

: 0 < x < 1,

Concave Upward

: 1 < x < \infty

Plug

into

x 36 - x^{2}

f (x) = 17 - 5 x

x^{3} - 4

f (x) = \frac{( x + 1 )}{( x + 2 )}

\frac{2 x ^{2} + 2 x - 12}{x ^{2} + x}

What is the inflection f(x)= x/(x^3-1) ?
The inflection f(x)= x/(x^3-1) is (-\sqrt[3]{2},(\sqrt[3]{2})/3)