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Popular >

inverse of 1/(s^2+9)

Solution

inverse

\frac{1}{s ^{2} + 9}

Solution

\frac{1 - 9 s}{s}, - \frac{1 - 9 s}{s}

Solution steps

y = \frac{1}{s ^{2} + 9}

Replace

s

with

y

s = \frac{1}{y ^{2} + 9}

Solve for

y, s = \frac{1}{y ^{2} + 9}

\frac{1 - 9 s}{s}, - \frac{1 - 9 s}{s}

Popular Examples

shift 6sin(3x-pi)shift

6 sin (3 x - π)

inverse of f(x)=x^2+8,x>= 0 inverse

f (x) = x^{2} + 8, x \geq 0

domain of f(x)=-1/2 domain

f (x) = - \frac{1}{2}

extreme f(x)=-5x^3-2x^4 extreme points

f (x) = - 5 x^{3} - 2 x^{4}

inverse of f(x)=4x+9 inverse

f (x) = 4 x + 9

Frequently Asked Questions (FAQ)

What is the inverse of 1/(s^2+9) ?
The inverse of 1/(s^2+9) is sqrt((1-9s)/s),-sqrt((1-9s)/s)