What is the critical f(x)=x^{7/3}-x^{4/3} ?

The critical f(x)=x^{7/3}-x^{4/3} is x=0,x= 4/7

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critical f(x)=x^{7/3}-x^{4/3}

critical points

f (x) = x^{\frac{7}{3}} - x^{\frac{4}{3}}

x = 0, x = \frac{4}{7}

Solution steps

x^{\frac{7}{3}} - x^{\frac{4}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{4}{7}

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{7}{3}} - x^{\frac{4}{3}} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{4}{7}

f (x) = \frac{x + 2}{3 x - 5}

e^{l n (x)}

f (x) = 100 - 4 x

f (x) = \frac{x ^{5} - 1}{3}

3 x^{4} - 6 x^{2}

What is the critical f(x)=x^{7/3}-x^{4/3} ?
The critical f(x)=x^{7/3}-x^{4/3} is x=0,x= 4/7