What is the domain of f(x)=sqrt(x^2+8x) ?

The domain of f(x)=sqrt(x^2+8x) is x = 0

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domain of f(x)=sqrt(x^2+8x)

domain

f (x) = x^{2} + 8 x

x \leq - 8 or x \geq 0

Interval Notation

(- \infty, - 8] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 8 or x \geq 0

The function domain

x \leq - 8 or x \geq 0

(6, 1), (- 1, - 3)

f (x) = \frac{5 - x}{x ^{2} - 2 x}

\frac{2 x - 3}{x + 1}

f (x) = \frac{x}{2 x + 5}

f (x) = x - 5

What is the domain of f(x)=sqrt(x^2+8x) ?
The domain of f(x)=sqrt(x^2+8x) is x<=-8\lor x>= 0