What is the domain of (ln(x-1))/(x-1) ?

The domain of (ln(x-1))/(x-1) is x>1

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domain of (ln(x-1))/(x-1)

domain

\frac{ln ( x - 1 )}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

(2, 3), (3, 7)

f (x) = \frac{3}{2} (2 x + 1)

- 4 cos (2 π x) + 2

f (x) = \frac{4 x + 4}{x ^{2} + 4 x + 3}

f (x) = \frac{x - 4}{x - 1}