What is the inverse of f(x)=((x+1))/(x-2) ?

The inverse of f(x)=((x+1))/(x-2) is (1+2x)/(x-1)

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inverse of f(x)=((x+1))/(x-2)

inverse

f (x) = \frac{( x + 1 )}{x - 2}

\frac{1 + 2 x}{x - 1}

Solution steps

y = \frac{x + 1}{x - 2}

Replace

x

with

y

x = \frac{y + 1}{y - 2}

Solve for

y, x = \frac{y + 1}{y - 2}

\frac{1 + 2 x}{x - 1}

(- 3, 10), (20, - 5)

x^{\frac{1}{5}} (x + 6)

\frac{5}{t}

\frac{3 x + 1}{2 x - 7}

f (x) = x^{2} - 4 x

What is the inverse of f(x)=((x+1))/(x-2) ?
The inverse of f(x)=((x+1))/(x-2) is (1+2x)/(x-1)