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Popular >

extreme y=x^2+x-6

Solution

extreme points

y = x^{2} + x - 6

Solution

Minimum (- \frac{1}{2}, - \frac{25}{4})

Solution steps

f^{'} (x) = 2 x + 1

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{2},

Increasing

: - \frac{1}{2} < x < \infty

Plug

x = - \frac{1}{2}

into

x^{2} + x - 6 : - \frac{25}{4}

Minimum (- \frac{1}{2}, - \frac{25}{4})

Popular Examples

inverse of f(x)= 2/(-x+1)-2 inverse

f (x) = \frac{2}{- x + 1} - 2

asymptotes of (x^2-2x-8)/(x^2-7x+12)asymptotes

\frac{x ^{2} - 2 x - 8}{x ^{2} - 7 x + 12}

asymptotes of f(x)=(-7x^2+1)/(x^2+x+8)asymptotes

f (x) = \frac{- 7 x ^{2} + 1}{x ^{2} + x + 8}

intercepts of f(x)=x^2+36 intercepts

f (x) = x^{2} + 36

perpendicular-2x perpendicular

- 2 x

Frequently Asked Questions (FAQ)

What is the extreme y=x^2+x-6 ?
The extreme y=x^2+x-6 is Minimum(-1/2 ,-25/4)