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Popular >

distance (2,8),(4,7)

Solution

distance

(2, 8), (4, 7)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, 8)

and

(4, 7)

is

= (4 - 2)^{2} + (7 - 8)^{2}

Simplify

= 5

Popular Examples

shift f(x)=-cos(1/2 (x+pi/2))shift

f (x) = - cos (\frac{1}{2} (x + \frac{π}{2}))

midpoint (6,-6),(-7,8)midpoint

(6, - 6), (- 7, 8)

extreme f(x)=(x^2)/(x-5)extreme points

f (x) = \frac{x ^{2}}{x - 5}

domain of f(x)=8x+12 domain

f (x) = 8 x + 12

asymptotes of f(x)= 4/(x+3)+2 asymptotes

f (x) = \frac{4}{x + 3} + 2

Frequently Asked Questions (FAQ)

What is the distance (2,8),(4,7) ?
The distance (2,8),(4,7) is square root of 5