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Popular >

extreme f(x)=x^2+7x+5

Solution

extreme points

f (x) = x^{2} + 7 x + 5

Solution

Minimum (- \frac{7}{2}, - \frac{29}{4})

Solution steps

f^{'} (x) = 2 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{2},

Increasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

x^{2} + 7 x + 5 : - \frac{29}{4}

Minimum (- \frac{7}{2}, - \frac{29}{4})

Popular Examples

intercepts of (2x^2-5x-12)/(x^2-16)intercepts

\frac{2 x ^{2} - 5 x - 12}{x ^{2} - 16}

intercepts of f(x)=2x+3y=-24 intercepts

f (x) = 2 x + 3 y = - 24

domain of f(x)=\sqrt[3]{3x+2}domain

perpendicular y=-1/3 x+3 perpendicular

y = - \frac{1}{3} x + 3

line (-17,19),(-4,26)line

(- 17, 19), (- 4, 26)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+7x+5 ?
The extreme f(x)=x^2+7x+5 is Minimum(-7/2 ,-29/4)