What is the domain of f(x)= 2/(sqrt(5+3x)) ?

The domain of f(x)= 2/(sqrt(5+3x)) is x>-5/3

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domain of f(x)= 2/(sqrt(5+3x))

domain

f (x) = \frac{2}{5 + 3 x}

x > - \frac{5}{3}

Interval Notation

(- \frac{5}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{5}{3}

Find undefined (singularity) points:

x = - \frac{5}{3}

Combine real regions and undefined points for final function domain

x > - \frac{5}{3}

x^{4} - 2 x^{3} - 9

f (x) = x + 5

f (x) = \frac{( x ^{2} )}{x ^{2} + 3}

f (x) = \frac{x ^{3} - 27}{x ^{2} - 5 x + 6}

f (x) = \frac{x - 13}{11}

What is the domain of f(x)= 2/(sqrt(5+3x)) ?
The domain of f(x)= 2/(sqrt(5+3x)) is x>-5/3