What is the range of (sqrt(x+1))/(sqrt(x-4)) ?

The range of (sqrt(x+1))/(sqrt(x-4)) is f(x)>1

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range of (sqrt(x+1))/(sqrt(x-4))

range

\frac{x + 1}{x - 4}

f (x) > 1

Interval Notation

(1, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x + 1}{x - 4} : x > 4

Simplify

\frac{x + 1}{x - 4} : \frac{x + 1}{x - 4}

Extreme Points of

\frac{x + 1}{x - 4} :

None

Find the range for the interval

4 < x < \infty : 1 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) > 1

x^{2} - 6 x + 9

f (x) = 2 x^{2} - 4 x - 3

x + 7 = 0

X^{3}

What is the range of (sqrt(x+1))/(sqrt(x-4)) ?
The range of (sqrt(x+1))/(sqrt(x-4)) is f(x)>1