What is the inverse of f(x)=((x+3))/((x-7)) ?

The inverse of f(x)=((x+3))/((x-7)) is (3+7x)/(x-1)

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inverse of f(x)=((x+3))/((x-7))

inverse

f (x) = \frac{( x + 3 )}{( x - 7 )}

\frac{3 + 7 x}{x - 1}

Solution steps

y = \frac{x + 3}{x - 7}

Replace

x

with

y

x = \frac{y + 3}{y - 7}

Solve for

y, x = \frac{y + 3}{y - 7}

\frac{3 + 7 x}{x - 1}

(- 3, - 1), (2, 3)

f (x) = \frac{6}{x}

y = 7

(1, 5), (7, 7)

1 + x^{2}

What is the inverse of f(x)=((x+3))/((x-7)) ?
The inverse of f(x)=((x+3))/((x-7)) is (3+7x)/(x-1)