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Popular >

extreme f(x)=(2x^2)/(x^2-9)

Solution

extreme points

f (x) = \frac{2 x ^{2}}{x ^{2} - 9}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{36 x}{( x ^{2} - 9 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 0,

Decreasing

: 0 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = 0

into

\frac{2 x ^{2}}{x ^{2} - 9} : 0

Maximum (0, 0)

Popular Examples

line y=2x+1 line

y = 2 x + 1

domain of f(x)=2x^2-5x domain

f (x) = 2 x^{2} - 5 x

asymptotes of f(x)=(-6)/(2x+1)asymptotes

f (x) = \frac{- 6}{2 x + 1}

intercepts of (15x^2)/(x+5)intercepts

\frac{15 x ^{2}}{x + 5}

asymptotes of f(x)=(-5x+20)/(x^2-16)asymptotes

f (x) = \frac{- 5 x + 20}{x ^{2} - 16}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(2x^2)/(x^2-9) ?
The extreme f(x)=(2x^2)/(x^2-9) is Maximum(0,0)