What is the extreme (x+1)/(sqrt(x^2+1)) ?

The extreme (x+1)/(sqrt(x^2+1)) is Maximum(1,sqrt(2))

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extreme (x+1)/(sqrt(x^2+1))

extreme points

\frac{x + 1}{x ^{2} + 1}

Maximum (1, 2)

Solution steps

f^{'} (x) = \frac{- x + 1}{( x ^{2} + 1 ) x ^{2} + 1}

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

\frac{x + 1}{x ^{2} + 1} : 2

Maximum (1, 2)

f (x) = \frac{4 x + 1}{3 - x}

- sin (\frac{1}{3} x) - 2

y = - \frac{3}{5} x + \frac{7}{5}

f (x) = x 5 - x

f (x) = 8 x^{3}

What is the extreme (x+1)/(sqrt(x^2+1)) ?
The extreme (x+1)/(sqrt(x^2+1)) is Maximum(1,sqrt(2))