What is the domain of f(x)=sqrt(x^4-81) ?

The domain of f(x)=sqrt(x^4-81) is x = 3

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domain of f(x)=sqrt(x^4-81)

domain

f (x) = x^{4} - 81

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

tan (- 2 x)

f (x) = (\frac{3}{2})^{x}

f (x) = \frac{( x - 2 )}{x ^{2} - 4}

f (x) = \frac{x}{x ^{2} - 2 x}

f (x) = \frac{x ^{3}}{3} - \frac{x ^{2}}{2}

What is the domain of f(x)=sqrt(x^4-81) ?
The domain of f(x)=sqrt(x^4-81) is x<=-3\lor x>= 3