What is the domain of 1/(x^2+8x-65) ?

The domain of 1/(x^2+8x-65) is x 5

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domain of 1/(x^2+8x-65)

domain

\frac{1}{x ^{2} + 8 x - 65}

x < - 13 or - 13 < x < 5 or x > 5

Interval Notation

(- \infty, - 13) \cup (- 13, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 13

The function domain

x < - 13 or - 13 < x < 5 or x > 5

\frac{6 x + 4}{2 x - 1}

\frac{4}{2 - x}

x^{2} - 12

f (x) = - x + 3

\frac{x - 6}{x + 6}

What is the domain of 1/(x^2+8x-65) ?
The domain of 1/(x^2+8x-65) is x<-13\lor-13<x<5\lor x>5